Triangle knowing the midpoint D of BC, the foot B' of the B-altitude and the midpoint Z between C and the orthocenter

1) Let B" be the reflection of B' in z
2) The parallel from B" to DZ and the perpendicular from B' to DZ intersect at C
3) The parallel from B' to DZ cuts CD at B
4) The perpendicular from B to CZ cuts CB' at A, and ABC is the requested triangle.